**Next message:**Lingxiao X: "Re：How to have a specific sin in the amplitude"**Previous message:**Vladyslav Shtabovenko: "Re: On the Contexts of FeynCalc"**Messages sorted by:**[ date ] [ thread ] [ subject ] [ author ]**Mail actions:**[ respond to this message ] [ mail a new topic ]

The function A0[M1^2] depends on D implicitly. Also it depends on regulator

mass (mass scale) \mu^2. If you need i can find and write out exact formula,

but this formula one can find in any reference book concerning

Passrino-Veltman integral functions.

----- Original Message -----

From: "Mr M." <noreply@feyncalc.org>

To: <feyncalc@feyncalc.org>

Sent: Friday, January 16, 2009 4:11 PM

Subject: SetOptions[OneLoop, Dimension -> D]

*> Hi, I am using FC-6.00 with Mathematica-6.03 and run into problem of not
*

*> being able to perform OneLoop integration for some arbitrary dimension D.
*

*> Here one example calc.
*

*> IN->
*

*> SetOptions[OneLoop, Dimension -> D];
*

*> TEST = OneLoop[k,
*

*> I*FourVector[k, \[Mu], Dimension -> D]*
*

*> FourVector[k, \[Nu], Dimension -> D]*FAD[{k, M1}]] // InputForm
*

*> OUT->
*

*> -(M1^2*Pi^2*(M1^2 + 2*A0[M1^2])*Pair[LorentzIndex[\[Mu]],
*

*> LorentzIndex[\[Nu]]])/8
*

*> I want to obtain the result being dependent of D, to cancel it later
*

*> manually. Am I missing something?
*

*>
*

*> Thanks.
*

*>
*

**Next message:**Lingxiao X: "Re：How to have a specific sin in the amplitude"**Previous message:**Vladyslav Shtabovenko: "Re: On the Contexts of FeynCalc"**Messages sorted by:**[ date ] [ thread ] [ subject ] [ author ]**Mail actions:**[ respond to this message ] [ mail a new topic ]

*
This archive was generated by hypermail 2b29
: 06/26/17-02:00:02 PM Z CEST
*